[Bash-completion-devel] Bug#521407: bash-completion: no completion for ls with variables

[David Paleino]

On Sat, 4 Apr 2009 22:49:26 +0200, David Paleino wrote:

> _longopt() {
>   [..]
>   if [[ "$cur" == -* ]]; then
>     [..]
>   elif [[ $(dequote "$cur") == "\$"* ]]; then
>     COMPREPLY=( $( compgen -v -P '$' -- "${cur//\$/}" ) )
>   elif [[ "$1" == rmdir ]]; then
>     [..]
> }
> 
> that doesn't work because the $ gets escaped, so one ends up with "ls
> \$OLDPWD", which doesn't work (obviously). I'm too tired to dig into the code,
> so if someone knows the reason why, is welcome :)

Ooookay, I found a similar snippet in _cd(), and that works :)

        # try to allow variable completion
        if [[ "$cur" == ?(\\)\$* ]]; then
                COMPREPLY=( $( compgen -v -P '$' -- "${cur#?(\\)$}" ) )
                return 0
        fi

However it still conflicts with -o filenames (!!! I wrote this without even
thinking. Is it really the culprit for escaping $?! Wow.)

Ideas?

David

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